In what state is the refrigerant when a line contains Ammonia at 80°F and 120 PSIG?

To determine the state of the refrigerant, one must consider the properties of ammonia at the given temperature and pressure. At 80°F and 120 PSIG, we first convert the pressure to absolute pressure (PSIA) by adding atmospheric pressure, which is approximately 14.7 PSIA. Therefore, 120 PSIG amounts to 134.7 PSIA.

Next, we consult the ammonia saturation tables, which provide information regarding the saturation temperature and pressure for ammonia. At 120 PSIG (134.7 PSIA), the saturation temperature is significantly lower than 80°F. This indicates that at 80°F, ammonia will not be in a saturated liquid or a mixture state, as the temperature exceeds the corresponding saturation temperature.

When the refrigerant is above its saturation temperature at a designated pressure, it exists in a vapor state. Therefore, at 80°F and 120 PSIG, ammonia is entirely in the vapor state. This aligns with the properties of the refrigerant, indicating that it has not condensed into liquid form and is not in any mixture state.

This understanding is crucial for anyone working in refrigeration, as it helps in assessing the conditions and behavior of refrigerants under varying temperatures and pressures.